The TMS320VC5506/C5507/C5509A USB peripherals can be clocked from either the USB APLL or the
USB DPLL. Since the APLL is inherently more noise tolerant and has less long-term jitter than the DPLL,
it is recommended that you switch to it for any USB operations.
A heap is a binary tree satisfying the following
conditions:
􀂄 This tree is completely balanced.
􀂄 If the height of this binary tree is h, then leaves
can be at level h or level h-1.
􀂄 All leaves at level h are as far to the left as
possible.
􀂄 The data associated wit ...
learning English The following appeared in a memorandum written by the vice president of Nature s Way, a chain of stores selling health food and other health-related products. "Previous experience has shown that our stores are most profitable in areas where residents are highly concerned with leadin ...
The existence of numerous imaging modalities makes it possible to present different data present in different modalities together thus forming multimodal images. Component images forming multimodal images should be aligned, or registered so that all the data, coming from the different modalities, ar ...
Here are the functions for Hamming code 7.4 and Extended Hamming code 8.4
encoding and decoding.
For 7.4 code, one error per 7-bit codeword can be corrected.
For 8.4 code, one error per 8-bit codeword can be corrected
and not less than 2 errors can be detected.
S60 SDL is a Simple DirectMedia Layer adaptation for S60. SDL is a cross-platform multimedia library: Applications and libraries built on SDL can easily be ported to other operating systems. But S60 SDL does more than makes porting easy: S60 multimedia applications can be implemented without any kno ...
OTSU Gray-level image segmentation using Otsu s method.
Iseg = OTSU(I,n) computes a segmented image (Iseg) containing n classes
by means of Otsu s n-thresholding method (Otsu N, A Threshold Selection
Method from Gray-Level Histograms, IEEE Trans. Syst. Man Cybern.
9:62-66 1979). Thre ...
Heapsort
1.A heap is a binary tree satisfying the followingconditions:
-This tree is completely balanced.
-If the height of this binary tree is h, then leaves can be at level h or level h-1.
-All leaves at level h are as far to the left as possible.
-The data associated with all descendants of a nod ...
Generate Possion Dis.
step1:Generate a random number between [0,1]
step2:Let u=F(x)=1-[(1/e)x]
step3:Slove x=1/F(u)
step4:Repeat Step1~Step3 by using different u,you can get x1,x2,x3,...,xn
step5:If the first packet was generated at time [0], than the
second packet will be generated at time ...
