这个压缩包里的都是超级经典的java例子

源代码在线查看: coll_findinlist.htm

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				Finding an Element in a Sorted List (Java Developers Almanac Example)
				
				
				
				
				
				
				
				
				
				
				
				
				
				
				
				
				
				
				
				
				
				The Java Developers Almanac 1.4
				
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				Home
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				    List of Packages
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				    java.util
				         [51 examples]
				    
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				        Sorted Collections
				             [6 examples]
				            
				
				  e362. Finding an Element in a Sorted List
				
				
				    // Create a list with an ordered list of strings
				    List sortedList = new LinkedList();
				    sortedList.addAll(Arrays.asList(new String[]{"ant", "bat", "cat", "dog"}));
				    
				    // Search for the word "cat"
				    int index = Collections.binarySearch(sortedList, "cat");    // 2
				    
				    // Search for a non-existent element
				    index = Collections.binarySearch(sortedList, "cow");        // -4
				
				A negative return value indicates that the element is not in the list.
				However, the actual return value can be used to determine where that
				non-existent element should be inserted in the list if that were desired;
				see e363 Inserting an Element into a Sorted List.
				
				
				
				
				             Related Examples
				
				
				
				
				e358. 
				    Creating a Sorted Set
				
				
				
				e359. 
				    Sorting an Array
				
				
				
				e360. 
				    Finding an Element in a Sorted Array
				
				
				
				e361. 
				    Inserting an Element into a Sorted Array
				
				
				
				e363. 
				    Inserting an Element into a Sorted List
				
				
				
				
				
				
				
				
				        See also: 
				
				    Arrays
				  
				
				
				    Bits
				  
				
				
				    Collections
				  
				
				
				    Dates
				  
				
				
				    Hash Tables
				  
				
				
				    Lists
				  
				
				
				    Property Files
				  
				
				
				    Sets
				  
				
				
				    Time
				  
				
				
				    Timers
				  
				
				
				
				
				
				
				
				
				
				© 2002 Addison-Wesley.
				   
				
				
				
				
				
				
				
				
							

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