都是大家需要的程序,大家要下的快下,大家要多多支持

				a=0;b=1;N=10;
				h=(b-a)/N;
				T(1,1)=(b-a)*(ft(a)+ft(b))/2;
				%while (i>1)
				for i=2:10
				       sum=0;
				       for k=1:2^(i-2)
				           sum=sum+ft(a+(2*k-1)*(b-a)/2^(i-1));
				       end
				           T(1,i)=(T(1,i-1)+(b-a)*sum/(2^(i-2)))/2;
				       for m=1:i
				           for k=2:i-m+1
				               T(m+1,k-1)=(4^m*T(m,k)-T(m,k-1))/(4^m-1);
				                
				           end
				           
				       end
				                 
				end