linux-2.4.29操作系统的源码

源代码在线查看: ev67-strncat.s

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关键词: linux 29 操作系统 源码
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				/*				 * arch/alpha/lib/ev67-strncat.S				 * 21264 version contributed by Rick Gorton 				 *				 * Append no more than COUNT characters from the null-terminated string SRC				 * to the null-terminated string DST.  Always null-terminate the new DST.				 *				 * This differs slightly from the semantics in libc in that we never write				 * past count, whereas libc may write to count+1.  This follows the generic				 * implementation in lib/string.c and is, IMHO, more sensible.				 *				 * Much of the information about 21264 scheduling/coding comes from:				 *	Compiler Writer's Guide for the Alpha 21264				 *	abbreviated as 'CWG' in other comments here				 *	ftp.digital.com/pub/Digital/info/semiconductor/literature/dsc-library.html				 * Scheduling notation:				 *	E	- either cluster				 *	U	- upper subcluster; U0 - subcluster U0; U1 - subcluster U1				 *	L	- lower subcluster; L0 - subcluster L0; L1 - subcluster L1				 * Try not to change the actual algorithm if possible for consistency.				 */													.text									.align 4					.globl strncat					.ent strncat				strncat:					.frame $30, 0, $26					.prologue 0									mov	$16, $0		# set up return value					beq	$18, $zerocount	# U :					/* Find the end of the string.  */					ldq_u   $1, 0($16)	# L : load first quadword ($16 may be misaligned)					lda     $2, -1($31)	# E :									insqh   $2, $0, $2	# U :					andnot  $16, 7, $16	# E :					nop			# E :					or      $2, $1, $1	# E :									nop			# E :					nop			# E :					cmpbge  $31, $1, $2	# E : bits set iff byte == 0					bne     $2, $found	# U :								$loop:	ldq     $1, 8($16)	# L :					addq    $16, 8, $16	# E :					cmpbge  $31, $1, $2	# E :					beq     $2, $loop	# U :								$found:	cttz	$2, $3		# U0 :					addq	$16, $3, $16	# E :					nop			# E :					bsr	$23, __stxncpy	# L0 :/* Now do the append.  */									/* Worry about the null termination.  */									zapnot	$1, $27, $2	# U : was last byte a null?					cmplt	$27, $24, $5	# E : did we fill the buffer completely?					bne	$2, 0f		# U :					ret			# L0 :								0:	or	$5, $18, $2	# E :					nop					bne	$2, 2f		# U :					and	$24, 0x80, $3	# E : no zero next byte									nop			# E :					bne	$3, 1f		# U :					/* Here there are bytes left in the current word.  Clear one.  */					addq	$24, $24, $24	# E : end-of-count bit 					nop			# E :								2:	zap	$1, $24, $1	# U :					nop			# E :					stq_u	$1, 0($16)	# L :					ret			# L0 :								1:	/* Here we must clear the first byte of the next DST word */					stb	$31, 8($16)	# L :					nop			# E :					nop			# E :					ret			# L0 :								$zerocount:					nop			# E :					nop			# E :					nop			# E :					ret			# L0 :									.end strncat							

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