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				Shell源码:find查找日期为某一天的文件
				 
				
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				第八军团 时间：2004-1-23 15:51:08 
				   
				 A=`find ~ -print` | ls -l --full-time $A 2>/dev/null | grep "Jun 27"  | grep 1998  
				   Linux的命令很厉害的呀！  
				   给你写了下面这个script，用着方便点儿。你把它存成一个随便什么名字的文件,置上x属性就行了。  
				   #!/bin/sh  
				   # Copyright by Ming Gong(宫敏) for news://news.freesoft.cei.gov.cn/chinese.com.linux  
				   # GPL V2, Jun 30, 1998  
				   # The right of usage, distribution and modification is here by granted by the author.  
				   # The author deny any responsibilities and liabilities related to the code.  
				   #  
				   OK=0  
				   A=`find $1 -print`  
				   if expr $3 == 1 >/dev/null  ; then M=Jan ; OK=1 ; fi  
				   if expr $3 == 2 >/dev/null  ; then M=Feb ; OK=1 ; fi  
				   if expr $3 == 3 >/dev/null  ; then M=Mar ; OK=1 ; fi  
				   if expr $3 == 4 >/dev/null  ; then M=Apr ; OK=1 ; fi  
				   if expr $3 == 5 >/dev/null  ; then M=May ; OK=1 ; fi  
				   if expr $3 == 6 >/dev/null  ; then M=Jun ; OK=1 ; fi  
				   if expr $3 == 7 >/dev/null  ; then M=Jul ; OK=1 ; fi  
				   if expr $3 == 8 >/dev/null  ; then M=Aug ; OK=1 ; fi  
				   if expr $3 == 9 >/dev/null  ; then M=Sep ; OK=1 ; fi  
				   if expr $3 == 10 >/dev/null  ; then M=Oct ; OK=1 ; fi  
				   if expr $3 == 11 >/dev/null  ; then M=Nov ; OK=1 ; fi  
				   if expr $3 == 12 >/dev/null  ; then M=Dec ; OK=1 ; fi  
				   if expr $3 == 1 >/dev/null  ; then M=Jan ; OK=1 ; fi  
				
				   if expr $OK == 1 > /dev/null ; then  
				     ls -l --full-time $A 2>/dev/null | grep "$M $4" | grep $2 ;  
				   else  
				     echo Usage: $0 path Year Month Day;  
				     echo Example: $0 ~ 1998 6 30;  
				   fi